4[2-(2x-2)]=2(4-3x)

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Solution for 4[2-(2x-2)]=2(4-3x) equation:


Simplifying
4[2 + -1(2x + -2)] = 2(4 + -3x)

Reorder the terms:
4[2 + -1(-2 + 2x)] = 2(4 + -3x)
4[2 + (-2 * -1 + 2x * -1)] = 2(4 + -3x)
4[2 + (2 + -2x)] = 2(4 + -3x)

Combine like terms: 2 + 2 = 4
4[4 + -2x] = 2(4 + -3x)
[4 * 4 + -2x * 4] = 2(4 + -3x)
[16 + -8x] = 2(4 + -3x)
16 + -8x = (4 * 2 + -3x * 2)
16 + -8x = (8 + -6x)

Solving
16 + -8x = 8 + -6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6x' to each side of the equation.
16 + -8x + 6x = 8 + -6x + 6x

Combine like terms: -8x + 6x = -2x
16 + -2x = 8 + -6x + 6x

Combine like terms: -6x + 6x = 0
16 + -2x = 8 + 0
16 + -2x = 8

Add '-16' to each side of the equation.
16 + -16 + -2x = 8 + -16

Combine like terms: 16 + -16 = 0
0 + -2x = 8 + -16
-2x = 8 + -16

Combine like terms: 8 + -16 = -8
-2x = -8

Divide each side by '-2'.
x = 4

Simplifying
x = 4

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